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Configuration = 112
cycles = (10 4 2 9 3)(8 6 1 7 5)

a = 1, b = 2, c = 9
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cycles = (10 3 1 6 4 7 5 8 2)(9)

a = 2, b = 5, c = 8
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cycles = (10 6 1 3 7 4 2)(9)(8)(5)

a = 1, b = 3, c = 6
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cycles = (10 6 7 2 5)(9)(8)(4)(3)(1)

a = 6, b = 7, c = 10
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cycles = (10 2 5)(9)(8)(7)(6)(4)(3)(1)